1. What version of GopherLua are you using?

[email protected]

2. What version of Go are you using? :

go version go1.21.4 darwin/amd64

3. What operating system and processor architecture are you using?

Mac OS Catalina 10.15.3 x86_64

4. What did you do?

i do this: (go) L.DoFile -> (lua)xpcall -> (lua)dofile
here the code
golang:

   L := lua.NewState()
   defer L.Close()

   if err := L.DoFile("init.lua"); err != nil {
   	fmt.Println(err.Error())
   }

init.lua

xpcall(dofile, printErr, "first.lua")	-- not work

first.lua

print("sth.")

5. What did you expect to see?

:L.DoFile should return，and first.lua should run

6. What did you see instead?

:go stuck there, only happens when xpcall -> dofile

➜  goluadofile ls
first.lua init.lua  run.go
➜  goluadofile go run ./run.go
start go run
[init] start
run_path:	init
^Csignal: interrupt

always stuck until ^C to interrupt it.

7. here are all source code files:
   run.go

package main

import (
	"fmt"

	lua "github.com/yuin/gopher-lua"
)

func main() {
	fmt.Println("start go run")

	L := lua.NewState()
	defer L.Close()

	if err := L.DoFile("init.lua"); err != nil {
		fmt.Println(err.Error())
	}
	fmt.Println("end go run")
}

init.lua

local function printErr(err)
	print(err)
	print(debug.traceback())
end

local function test( ... )
	print("is test function run, args: ", ...)
end

run_path = "init"
print("[init] start")


print("run_path:", run_path)

-- xpcall(test, printErr, "test")	-- work fine

-- dofile("first.lua")			-- work fine

-- pcall(dofile, "first.lua")	-- work fine

xpcall(dofile, printErr, "first.lua")	-- not work


print("run_path:", run_path)

print("[init] end")

first.lua

print("[first] start")
run_path = "first"
print("[first] end")

8. I don’t know if I set lua.NewState() up wrong, never mind to give more information